Music: Practice & Theory Stack Exchange is a question and answer site for musicians, students, and enthusiasts. It's 100% free, no registration required.

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I have started recording band practices. I'd like to record my guitar signal twice, one DI with no effects and the other mic'ing my amp. So I want to split my signal prior to effects chain (maybe post wah, which is the 1st effect in my chain). What do I need to do this?

If I just use a simple cable splitter, I assume I'll cut my signal in half and lose tone. Is that right? I'm guessing that I need some sort of A/B/Y pedal to use in the Y mode. What should I be looking for in that pedal? What distinguishes a bad from a good splitter pedal? Am I just looking for a good buffer? Are there options other than an ABY pedal, like maybe a tuner with two outputs?

share|improve this question

Yes, a simple cable splitter is a bad idea, and an ABY pedal will solve that problem---but you don't even need that. If you have an active DI with an unbalanced, buffered 1/4" out, you can simply send that to the effects and amp while sending the balanced XLR out (which will still be dry) directly to the board. Here's an example of what I'm talking about; I'm not familiar with this specific make & model, though, so this isn't a product recommendation.

share|improve this answer
I don't have one lying around. Is that better than using an aby box? – yossarian Jan 3 '12 at 13:13
@yossarian Better? I can't imagine it is, but unless you already have an active ABY box (and if you did, why would you have posted?), it seems to me you're going to be buying a gadget anyway, in which case the active DI solution seems simpler---to me, anyway. – Alex Basson Jan 3 '12 at 13:31

Actually, although an active DI is probably a good idea, a passive DI will solve the same problem.

A DI box is little more than an electrical transformer; the "hot" side of the unbalanced signal is wound around one side of a ferrous metal ring. On the other side of the ring is another loop of wire that feeds the "balanced" output. Alternating current produced by the instrument passes through the loop one one side, and induces a magnetic field in the ring. The magnetic field then induces a current in the loop of wire on the opposite side.

While this process is "work", and will thus reduce the remaining power of the signal, an XLR signal is expected to be 20dBm less powerful than most unbalanced signals. A 10dB change is an increase or reduction of 10x the original signal, so a signal that is 20dBm lower than another is 1/100 or 1% of the wattage of that signal. So, your original signal loses 1% (plus a little overhead) of its original wattage to create the balanced XLR signal. I guarantee you that you will not notice a loss of 1% of your signal wattage; that's less than 1dB, and 3dB is the minimum change in volume level that a human can notice.

You still shouldn't use a Y-splitter; this will form a parallel circuit, with very low impedance (an "easy" path) on the side of the DI. That will cause most of the signal (not just half; almost all, really) to go through the DI side of the split and back into the instrument, instead of the very high-impedance path through the pedals and into the amp. Instead, use the DI's "thru" input, which engages either passive circuitry that puts the transformer in series with the rest of the chain, or active circuitry that includes a gain stage to boost the "thru" signal back up to its original level. Either way, you should be able to plug the DI into your effects chain with a couple of simple patch cables, like any other "effect", and see little difference in tone. The better the DI, the less it will color your tone; Radial is a good brand but you'll pay for it.

share|improve this answer
Signal wattage is not that relevant here, the problem with passive DIs is that they interact with the guitar pickups' high inductive impedance and can thereby alter the sound quite substantially. As for the "thru" jack – to be honest I haven't looked in many DIs, but I'm quite sure that it's also simply wired parallel on most models, so that would yield exactly the same result as a Y-cable. – leftaroundabout Mar 1 '12 at 22:53

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.