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As the PC Set Calculator you link to shows, [0, 1, 2, 3, 5] is the Prime Inversion of [0, 2, 3, 4, 5]. However, as [0, 1, 2, 3, 5] has a lower interval at the bottom, it is considered the correct prime form of these two equivalent PC Sets. Another page on the website you link to gives a rigorous method for determining the Prime Form of any PC Set. The last ...


2

I think you forgot to test inversions -- you should measure the distance between the first two and last two classes, and find the form that packs the smaller intervals to the left. If you invert [0 2 3 4 5], you get [0 1 2 3 5], which succeeds in packing the shorter distance to the left of the form (starts with a distance of 1 instead of 2).



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