Timeline for How is it that 12 eighth notes fit in a measure labeled as common time?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Feb 4, 2016 at 18:03 | comment | added | Graham | Further to this, it's pretty common for the first bar to be notated as triplets, then write "simile" on the next bar, and job done for the rest of the piece. | |
| Feb 4, 2016 at 17:53 | comment | added | Darrel Hoffman | This lax notation is actually not uncommon for Liszt (and some of his contemporaries like Chopin). Many times, a run will be seen with an arbitrary number of notes that doesn't rhythmically divide into the measure in any fashion whatsoever, like 17 notes or something like that. He was generally more concerned with the melodic flow of the notes than their mathematical precision. | |
| Feb 3, 2016 at 21:14 | comment | added | Todd Wilcox | @KJPrice The treble (right hand) notes in the second half of the last measure are regular eighth notes. 1) They are beamed in a group of four. 2) They add up along with the half note to a 4/4 measure. 3) They are spaced in the measure like 8th notes. The triplets/12tuplets in the left hand are not spaced the way 8th notes are which is why they aren't lined up with the "real" 8th notes. Also the left hand notes (bass) are all beamed in one group which would not be done with normal 8th notes. Finally, they don't add up to a 4/4 measure (which is what prompted your question, of course). | |
| Feb 3, 2016 at 21:10 | comment | added | KJ Price | Can you please explain the bit about the eight notes in the right hand being normal? Are you referring to those in the base? They seem to be the same as the eighth notes on the left. Or are you referring to the treble notes on the right? | |
| Feb 3, 2016 at 21:02 | history | answered | MattPutnam | CC BY-SA 3.0 |