Timeline for Intervals: Diminished unison?
Current License: CC BY-SA 4.0
17 events
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| Feb 21, 2023 at 19:23 | review | Suggested edits | |||
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| Sep 21, 2018 at 11:20 | comment | added | Heather S. | @Richard, when C is still the starting note, an augmented octave would be C#. It is only Cb to C if you change the starting note to Cb, which is not the starting note in question. | |
| Sep 21, 2018 at 11:17 | comment | added | Heather S. | @Richard, I also believe in this situation, it would be an inversion since in addressing the "compound" interval, you are bringing the upper note below the original. In compound situations, the relation of notes as far as top/bottom does not change. As, in your answer, the D a tenth below the F, no longer compound, is still a 3rd below the F. | |
| Sep 21, 2018 at 11:15 | comment | added | Richard | @HeatherS. I'm not sure I understand what you mean. In my post I wasn't discussing inverting the interval. I only mentioned it in my last comment to show that that logic also supports my argument of this interval being C to C♭. | |
| Sep 21, 2018 at 11:13 | comment | added | Heather S. | @Richard, that changes the base note and direction, so I don't see how that helps answer the question. | |
| Sep 21, 2018 at 11:11 | comment | added | Richard | @HeatherS. I only meant switching between the compound and simple version of an interval (not inverting it), hence the quality stays the same. But you're correct, inverting intervals does change the size and quality, and this example shows that the diminished unison would be C to C♭, since the augmented octave would be C♭ to C! | |
| Sep 21, 2018 at 11:09 | comment | added | Heather S. | I do not understand your octave equivalence statement since in every other situation, an inverted interval changes both name and size. A P5 above a given note become a P4 below, a M6 above becomes a m3 below, etc. The inverted interval of a d8 would be an +unison, which is what we have here in C to Cb. | |
| Sep 19, 2018 at 23:10 | comment | added | Richard | @JiK In my opinion, they're the same thing, but "diminished unison" is admittedly more theoretical and not all that practical. | |
| Sep 19, 2018 at 23:07 | comment | added | JiK | Why would C-Cb be diminished unison and not a descending augmented unison? Is "diminished unison" just a play on following some written rules or is it a real thing? After all, the rules were created to describe what's happening, not the other way round. | |
| Sep 19, 2018 at 20:07 | history | edited | Richard | CC BY-SA 4.0 |
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| Sep 19, 2018 at 20:00 | comment | added | Richard | @Aethenosity Yes, which is why I tried to stay away from terms like "larger" and "smaller" when discussing that particular interval. | |
| Sep 19, 2018 at 19:53 | comment | added | Aethenosity | @Richard diminishing a unison would make the interval larger in the case of a unison though, right? The unison would have an interval of nothing, and a diminished unison would have an interval of a semi tone. | |
| Sep 19, 2018 at 6:35 | comment | added | Tim | In a way this sort of mocks the idea that intervals are worked out from the lower note! And, diminished means smaller. By going C>Cb, it's actually bigger! Also can't think of a reason for a dim 1, except for exam purposes. +1. | |
| Sep 19, 2018 at 0:49 | vote | accept | iiRosie1 | ||
| Sep 19, 2018 at 0:47 | comment | added | Richard | @iiRosie1 Correct. Maybe more correct would be that you make the interval smaller to make it diminished, and you make the interval larger to make it augmented. This is because you'll move the pitch in various directions depending on if it's above or below the other pitch. | |
| Sep 19, 2018 at 0:43 | comment | added | iiRosie1 | Ok, so a unison interval is basically perfect (no major or minor), and if you want to diminish it you just lower it by a semitone, and if you want to make it augmented, you basically raise it by a semitone? | |
| Sep 19, 2018 at 0:41 | history | answered | Richard | CC BY-SA 4.0 |