I am learning to play Scriabin’s 5 Preludes Op. 16 No. 4. The piece is in 3/4 but the first measure has a quarter note, two eighth notes, and then an eighth note + dotted eighth + sixteenth. This would add up to 3.5 beats instead of three. Is the last beat some sort of uneven triplet? Would appreciate help on how to count count this measure.
2 Answers
Yes, it's an uneven triplet. Most of the scores I've seen (IMSLP, for example) don't explicitly mark it as such, but here's one that does:
(Image source: IMSLP, Philippe Hézaine edition)
To count it, think of dividing each beat into six parts.
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1For the second line in the question’s image, the alignment with the lower staff is inconsistent. Commented Oct 2 at 6:22
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5Do you have any idea why most editions omit the triplet mark? I understand when it's omitted in repetition of a recurring pattern, but it's strange at the very beginning of a piece. Commented Oct 2 at 7:27
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@user1079505 I don't, but a glance through the first edition, all five pieces, revealed only one triplet marked as such — a quarter-note, eighth-note rhythm, where there's no beam to clarify the rhythmic grouping. There are plenty of eighth-note triplets throughout, but none of them are explicitly marked.– AaronCommented Oct 2 at 17:57
Aaron's answer as in the first example makes sense, but my first thought was maybe it meant the second example.
But a missing 3
triplet figure is more plausible than missing beam! Especially when considering that after the first inclusion of triplet 3
figures a score often omits them through the rest of the music.
Just to be clear, I agree with Aaron's answer that it should be a triplet figure, but I also wanted to point out a dotted sixteenth would fix the figure too.