Hi Im new to the site so please inform me if I am doing anything wrong.

So,4 arpeggiated chords all sixteenth notes The arpeggio goes as follows:


D-F-G-B -D-F-G-B

C#-F-G-A# -C#-F-G-A#

C-F-G-A# C-G-A#-C

My speculations are that it is either an

Fm-G7-Gm-Cm (iv-V7-v-i)

a somewhat classic chord progression leading to the tonic



Something like a descending kind of progression wich Im not aware of...

Or maybe a mix of these two?How you guys would analyse this and what is its harmonic function?Thanks in advance.Sorry for bad english!

1 Answer 1


Some of the enharmonics are confusing you, I think.

F-G-G#-C-D# is better understood with Ab and Eb instead of G# and D#. This is just an F9 chord.

D-F-G-B is a G7 chord.

C#-F-G-A# is also better understood with Db and Bb; this is a G7b5 (aka G half-diminished seventh).

C-F-G-A#, once again should be conceptualized with a Bb instead of an A#. This is a C7sus4.

Note that I'm not accounting for inversions, but definitely pay attention to the descending chromatic motion in (what I am assuming is) the lowest voice.

  • No arguments about the enharmonics, but, given that it appears that G is held as a pedal through the last three chords, then if the D♭ of the third chord is in the bass, you've got a fairly standard Phrygian ♭vii6 as a passing harmony between G7 and C7. I say "appears" advisedly - it seems persistent enough to be a pedal note, but it would be nice to see the score to see if the Gs appear at the same octave. If so, even arpeggiated they will act as a pedal.
    – user16935
    Dec 12, 2016 at 0:10
  • I agree 100%; it's always tough to analyze harmonies without a larger context.
    – Richard
    Dec 12, 2016 at 0:27
  • That first chord would be an F minor 9th, not an F9. Also the second chord includes a #9.
    – vjones
    Dec 13, 2016 at 0:18

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.