For the sake of the rhythmic analysis I'm doing, I had the idea to solder a wire to a metal pick, ground the strings and rig something up that sends data to a computer every time the pick touches a string and completes the circuit. But would doing so affect the sound of the guitar and be heard once amplified?

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    The strings are already grounded. Assuming you protect yourself from electrocution with proper capacitors and fuses, I say try it and found out. – Todd Wilcox Jan 24 '17 at 6:15
  • If the pick [presumably metal] were to be the only contact point, you'd also have to wear insulating gloves to play it. – Tetsujin Jan 24 '17 at 8:31
  • It's been done, more or less: amazon.com/Otamatone-from-Maywa-Denki-White/dp/B002IGTOZQ – Carl Witthoft Jan 24 '17 at 12:33
  • Where are the strings already grounded? The amount of current I'd use would be extremely small; not even enough to feel, much less hurt you. I assumed that wearing shoes would be enough to keep me from being a ground, but that even without them the majority of the current would follow the wire, it having much less resistance than my body. – to_the_sun Jan 25 '17 at 0:18
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    Basic lesson from personal experience: never play an electric musical instrument or touch a microphone in bare feet on concrete. – Francis Phillips Feb 17 '20 at 18:11

Time for some physics!

A guitar pickup consists of two parts: a permanent magnet and a coil of wire. These can sense the motion of nearby ferric object (like a steel guitar string) by taking advantage of Faraday's Law, which says that whenever the magnetic field passing through a loop or coil of wire changes, it will cause a current to flow in that loop. In the case of a guitar pickup, the permanent magnet causes the steel in the string to become magnetized, creating an extra magnetic field through the coil. When the string is plucked, it moves closer and farther from the pickup, causing the magnetic field it sends through the pickup coil to change. This then causes a current to flow through the coil, and the amount of current in the coil fluctuates at the same frequency as the string. This current is the signal that is then multiplied by the amplifier.

If you were to run a current down a steel guitar string near a pickup, this current would also create its own magnetic field, and some of this magnetic field would pass through the pickup coil as well. This means that the pickup could in principle sense the presence of the current; but because of Faraday's law, the response of the pickup would depend on the rate of change of the current rather than the amount of current. A straightforward direct current would create a magnetic field that wouldn't change with respect to time, and so it wouldn't cause any additional current to flow in the pickup coil. On the other hand, any change in the amount of current flowing down the string would cause a changing magnetic field, creating an additional unwanted current in the pickup coil.

You mention that you will be connecting this to a computer, so you're dealing with DC currents while they're flowing. You'll thus have a constant amount of current flowing through the string, changing only when the pick makes or breaks contact with the string. I suspect that if your proposed setup has an audible effect, it will be in the form of a "click" or "pop" at these moments, since at that point the amount of current flowing through them (and the magnetic field they produce) is changing quite rapidly.

I would be very curious to know what the result of your experiment is, and whether my prediction is at all correct. Please do report back if you can (and don't electrocute yourself in the process!)

  • I tested this with a couple wires and a AAA 1.2v 800mA battery. It sounded exactly like a scratchy pot. Even without sending the current through the string (just connecting the battery in a circuit with itself) you could hear it up to about a foot away from the pickups. – to_the_sun Feb 13 '17 at 1:20
  • However, I've got another method I'm testing out which involves two picks with conductive paint on them glued together. The tips of the picks are as close as possible without touching and the idea is that when you strum, you connect a circuit. It works and, for whatever reason, there is no noise. For testing I was powering it with 5v from an Arduino. I think maybe the amperage it provides is only on the level of 20-40mA and maybe that's why it's silent? – to_the_sun Feb 13 '17 at 1:23
  • @to_the_sun: My guess is that since you have the "inbound" and "return" current paths close together, their magnetic fields mostly cancel each other out, and so the inductive effects I mentioned aren't nearly as large. For the best behavior, be sure to twist the leads together so that they don't accidentally separate — the closer together the leads are, the better the magnetic field cancellation will be. – Michael Seifert Feb 13 '17 at 14:46

Yes, as tiny currents will effect the pickup coils. They are specifically designed to detect small changes in a magnetic field.

  1. A way to minimize currents over the pickup coils is to strum or pluck below the pickups because the strings are grounded down by the bridge. If the guitar gas a pickup selector, you may use the ones further away from the bridge.
  2. A capacitive coupled pic may sense string proximity while inducing only the most extreamly low currents in the strings.
  3. Alternatively, it may be possible to do rhythmic analysis on music without using a sensor.
  • Sure they are designed to detect changes in a magnetic field. But those changes would be really small in the magnetic field (not much currect, only a single winding), and even that would be in a direction that the PU isn't optimized to pick up. Furthermore it would go with the same polarity in both coils of a humbucker, which would further cancel the level down. – leftaroundabout Feb 17 '20 at 17:23
  • @leftaroundabout The relativly low inductance of a string can result in a small time constant and a rapid change in magnetic field. Pickup coil having many many many turns are specally designed to pick that up. A humbucker circuit may cancle that some, but if you make electrical contact between two pickup coils in a humbucker circuit, you wont get the canceling, because the location of the pic define a curren loop over a wire segment. – Keith Reynolds Feb 17 '20 at 17:54
  • the time constant is irrelevant. Yes, the current can build up almost-instantaneously, but because the pickup has a much higher inductance (and is connected to a capacitor, namely the cable) this won't actually result in a higher output signal. – leftaroundabout Feb 17 '20 at 18:06
  • @leftaroundabout because current in a wire has a circular magnetic field. Parts of its field do interact with magnetic poles going through the coil. And though the guitar string represents a single wire, the coil is 1 to 1000+ transformer. – Keith Reynolds Feb 17 '20 at 18:08

It would not do all that much since the magnetic field lines of any current would form circles around the string and thus be perpendicular to what the pickups will pick up. Also there is no necessity for using significant amounts of current here.

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    If you pass current down the strings, it is easily picked up by pickups. I have used strings to carry signals of various types and it is amazing how tiny a current can be picked up. – Doktor Mayhem Jan 24 '17 at 13:44

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