In the first measure from this section of Schubert's Serenade, does the accidental on the ornamental C at the beginning affect the "regular" C that follows? And is that answer applicable to all ornaments?
-
2What if it did not? Then you'd have a triplet with C-B#-C, fingered 3-2-3. Wouldn't that be a bit weird?– GauthierMar 12, 2012 at 15:52
-
It would not be that weird because sometimes you can alternate fingers on the same note.– iddoberMar 12, 2012 at 16:32
-
1I'm with you fir the fingering. But not noting C-B#-C (although it could be defended for matching the harmony, but not in this case).– GauthierMar 12, 2012 at 17:07
Add a comment
|
2 Answers
Yes it does affect it, both in this specific case and also for any ornament notated within the staff. The accidental always remains in effect for the remainder of that measure. However, if the two notes are of different octaves, the first accidental does not change the latter notes. If a G5 is sharped, for example, all remaining G5's of the measure will be sharped. G4's, G6's or G's of any other octave will be left natural. A natural sign has the same rules as any other accidental.
It's obvious that B♯ will be played on the same piano key as C♮.
So, there would be no point in writing B♯ in the same triplet as two C ♮ notes. Thus it will be conclusive that the accidental shown in the beginning of the bar will continue, like all accidentals should, through to the end of that bar - but only affecting that particular octave of the note C.
