This is probably a stupid question but I've been trying to resolve it for a while now and due to low knowledge of music theory, I can't. I don't really know what key I'm in.
0
-
2Is this homework? In the key of E major, F♯m is the ii chord with a predominant function, D♯dim is the vii° chord with a dominant function. (It is the upper 3 notes of a B7 chord, which is the V7.) So... in E major you would resolve to...? – trw Feb 6 at 13:49
-
1another way to solve this problem is to try out chords until you find something that sounds good...*THEN* try to figure out what is going on. – b3ko Feb 6 at 14:18
-
There aren‘t any stupid questions, never! – Albrecht Hügli Feb 6 at 22:13
1
One way to do this is list out all the tones of the chords and then find a key signature they all belong to: D# F# A C#.
So follow the circle of fifths for sharp keys until you get a match...
1#: G/Em - F# 2#: D/Bm - F# C# 3#: A/F#m - F# C# G# 4#: E/C#m - F# C# G# D# ...
You should see that your set of notes matches E or C#m.
That's the 'mechanical' part of the issue, but now we get to the actual important part: there isn't a single answer to this question. Or, you might say it isn't answerable.
In E we could continue the harmony as ii viio6 I or ii viio6 V7.
In C#m we could continue the harmony as iv iio6 i6 or iv6 iio6/4 V7.
There are other possibilities.
You probably expect the answer to simply be 'it resolves to E major, because that 'resolves' the diminished triad treating it as the leading tone triad viio. But it's really wrong to think that is the one answer.
-
Beware of restricting yourself to diatonic chords in one key. II7 V7 I is as common as ii7 V7 I. – Laurence Payne Feb 6 at 14:58
-
1True. But, I only used the plain
ii(ivin minor) because that was the chord in the question. – Michael Curtis Feb 6 at 15:00
0
A nice solution would be:
Starting in A :
A - f# - d#dim - A/E - E7 - A -> I -vi - (vii°7) - I46 - V - I
d#dim would be a secondary vii°7 to A/E (I46) with the final E - A = V - I
