Hi I have trouble with tuplets. There is a tuplet that has different note values under the same beam ( 16 th. And 8th.) There are 4 16th notes and 1 8th note at the end. There is a number 6 under the beam. I think it is a sextuplet. I don't understand how the tuplet works and how I play it. Thanks.!
OK. You have not given us an image (which would really help) but lets try to analyse this.
So there are four 16th notes and one 8th note. The 8th note is worth two 16th notes isn't it. So you have a total of six 16th note lengths in all. Same length as three 8th notes.
So you are correct that it is a sextuplet, or to think of it another way, a triplet where two of the three notes have each been further subdivided into two notes.
The whole thing should add up to the length of a quarter note.
I am going to make the assumption that the beat is a quarter note: you need to divide this beat into three and further divide two of those three in half.
I know it sound complicated but its quite straightforward when you get it.
If it helps (and it might not, but I'll say it anyway) it is the same pattern as a bar of 3/4 where the first four notes are 8ths and the last one is a quarter.
Hope that helps