You'd Be So Nice to Come Home To chord function question

Question

I have been playing through You'd Be So Nice to Come Home To. I have a pretty good grasp of the song and the chord functions up to the final section. I am interested to know the function and substitutions for the final 8 bars.

My lead sheet has it as: D#diminished7, C/E, G#diminished7, Am7 D9, Ab7, D7b9, G7, C6, Bm7b5, E7b9

Where are these chords coming from, particularly the diminished chords, what was the thinking behind these substitutions and how would you approach playing over them?

Thanks very much!

Answer 1

I don't want to speculate on how representative that lead sheet might be of the original song, but the question about the dim7 chords in the posted chord progression can be answered regardless.

Dim7 chords are symmetric and there are many plausible explanations for why they "work" or what they do. One way is to not think about it, just play the dim7 in different songs and different contexts, and you'll learn how it works naturally. Another way is to see them as dominant chords, and because of the dim7 chord's symmetric nature, each dim7 can be seen as four different dominants. See this answer about how it works: Why don't diminished 7 passing chords work going downhill?

For the G#dim7 -> Am7 step this is clear: G# is the third of E7 and G#dim7 works as dominant for A-based chords. Or you can think of the G# as a leading note to A.

Why does the D#dim7 -> C/E step work? The D#dim7 doesn't work as a G7, so it's not a dominant for C? No, but it could work as a B7, which is a dominant for E ... so, bass goes to E, but the rest of the harmony goes to C?

Like I said, you could just as well play the song from the lead sheet, maybe play it in different keys, and learn the D#dim7 -> C/E step as an atomic basic ingredient that doesn't need any further explanations. Just like you probably don't need a theoretical explanation for why subdominant IV chords sound like they do. You just use them and that's it. :)

For me personally, one such "atomic" progression is C - Cdim7 - Dm7 - G7. Why does that work going to Dm? Maybe because there's the downwards motion of the minor third E-G -> D#-F# - > D-F ? But is that a reason? Can you generalize that and use it in other contexts?

Answer 2

I didn't compare the chords with any recording, so let's just assume they are correct. I hear that part in C major, so C is the I. My analysis would be

| V7/III | I | V7/vi | vi | V7/V subV7/V | V7/V V7 | I | [iim7(b5) V] => vi |

V7/III (D#dim7 which is just a rootless B7(b9)) resolves to I, which works because you have the E in the bass of the C chord (and even if you didn't have the E in the bass it would work as a deceptive resolution). Ab7 is the tritone sub of D7, and the last two chords are a iim7(b5) V leading to vi (i.e., Am).

Answer 3

There are (at least) two classic uses of dim7 chords in this style of harmony:

1. As a substitute for the V7 resolving to a minor. Eg Bdim7 to C minor. This works because the Bdim has everything G7b9 has, except the root. And the dominant G7b9 sounds pretty going to minor (the Ab and B natural colour notes are also great in the C minor scale).

2. Going to a major 7 - eg Cdim7 to Cmaj7. This is because the voice leading is appealing, rather than being a substitute. Here you get Eb leading to E and F#b to G. You hear jazz guys like Getz and so on do this a lot.

In this end sequence, we have both of these (in the other order). With them also being relative major and minor, and C/E sets up an E bass note just before the G#dim7 meaning you get even more of a hint of E7b9 without actually going there.

The other bars are pretty much "round the houses" cycle of 4ths - the Ab7 being a tritone sub for D7 (but that looks to me like a Real Book "addition" anyway more than anything else).

Answer 4

Whoever invented those chord names apparently didn't understand what was going on. Look at the original sheet music here: http://images.indianahistory.org/cdm/ref/collection/p16797coll1/id/1542

Ignoring the details of the bass notes, That gives

Cdim - - - | C - - - | F6 - - F | - - - Fm6 |

C - Ab7 - | - - G7 - | C - - - | - - F E7 | (Am)

Inventing a convoluted argument that "D#dim7 is just a rootless B7(b9)" is irrelevant, since Cdim7 is identical to D#dim7 - though the sheet music editor had enough musical sense to realize that the A in the voice part wouldn't be improved by doubling it, and a "less is more" Cdim chord will sound better than a Cdim7.

Sorting out the rest of the creative fiction in the OP's chord sequence is too tedious to spell out in detail.