It appears that violin bridges are typically designed asymmetrically to support the lower strings at a greater height from the fingerboard, as shown in this photo:
At the end of the fingerboard the G string is more than 1/4" higher than the E string.
Why is this done?
The downside of strings being further elevated from the fingerboard is greater difficulty in stopping them, especially at higher notes.
I do have two guesses as to the answer:
The lower strings have a greater motion of vibration, and so they have to be held further from the fingerboard to avoid hitting it as they vibrate. But at the nut end of the fingerboard the difference in elevation between G and E is marginal – less than 1/16" – so that doesn't seem to explain why the elevation at the bridge would have to be so much greater.
The bridge is skewed towards the fingering hand to make it slightly easier to reach the lower strings. But this doesn't make much sense because the entire instrument can be canted to achieve the same effect, without the drawback mentioned above.