eg. Liebestraum no. 3, right hand, bars 1 and 2.

Liebestraum sheet

also Schubert Impromptu op. 90 no. 3

Lastly, any idea how this is achieved in Sibelius/Musescore?


  • pedal notes? And why/how can the rests be played while the pedal's held on? Never understood that.
    – Tim
    Apr 20, 2020 at 9:29
  • I wouldn't ca it "pedal" because that "C" belongs to both chords - Ab and C7. Apr 20, 2020 at 12:31

2 Answers 2


Actually this is nothing else than an arpeggio.

You can notate it like simple 4 voices piano part. (s.below)

In German we call this Akkord-Zerlegung (that is translated in english chord analysis) but this is nothing else than a guitar accompaniment or by a harp. So I'd call it just an arpeggio with a sustained (bass) note.

You'll have to notate the voices in different layers, but then you'll have to hide the rests in some voices to get a readable sheet product.

Try to notate it the 4 voices in 4 different channels and systems and then mix them together in one grand staff.


any idea how this is achieved in Sibelius/Musescore?

Notate the in Sibelius 4 different voices:

or 2 voices in the treble clef and 2 voices in the bass clef:

and if you have all 4 voices in one staff you can separate them later:


You'll need different voices to notate these (see this MuseScore handbook page; Lilypond uses the same terminology).

I'm not sure this particular situation has a specific term. It looks like a melody-dominated homophony the right hand is doing a part of the accompanying, usually the job of the left hand.

Another well-known example is the first movement of Beethoven's Moonlight Sonata, which is described as follows:

A melody that Hector Berlioz called a "lamentation", mostly by the right hand, is played against an accompanying ostinato triplet rhythm, simultaneously played by the right hand.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.