In image 1, it's easy to play while counting in head or using a metronome, since the treble and bass notes are both divided by even numbers within a beat.
But in image 2, the treble notes are divided in odd number 3, so you count 1-trip-let, but in bass clef you count in even number 2, which is 1 and.
For the notes in image 2, how do you make sure you are counting and syncing your playing correctly?
UPDATE: Sorry for not asking a clearer question, I guess I'm really asking is how to sync the eighth rest with the remaining two triplet notes
UPDATE 2: I just realized this may be a lot simpler than I had thought, anytime you have different divisions in a column between the clefs, you can just use the lowest common denominator? Which should work with any numbers?
If the treble clef column is divided into 3 notes and the bass clef column is divided into 2 notes, then you just count with 6, since 6 is the lowest common denominator? Each top note is worth 2 and each bottom note is worth 3?
For just one of the columns that I outlined with a rectangle:
1 (first TREBLE note start and first BASS diad start)
2 (first TREBLE note sustaining and first BASS diad sustaining)
3 (second TREBLE note start and first BASS diad still sustaining)
4 (second TREBLE note sustaining and now the BASS diad is replaced by the REST)
5 (third TREBLE note start and BASS rest sustaining)
6 (third TREBLE note sustaining and BASS rest sustaining)
I guess for the whole bar you can count like this?
123456 223456 323456 423456
Not sure if this is remotely sensible but seems to work for me to be as exact as possible