New answers tagged

2

Some way to get this automatically: #(define (Beat_counter_engraver context) (let ((measpos #f) (grouping #f) (basemom #f) (beatmom #f)) (define (mom->dur mom) (let ((pair (moment->fraction mom))) (/ (car pair) (cdr pair)))) (define (is-beat-moment? count gping beatcount) (if (= (* count (mom->dur basemom)) (mom->dur ...


4

The target frequency (F4) is approximately 349.23Hz. You have to find a common divisor between those two frequencies, which coincidentally is the bar. So, assuming the frequency above, you can find that each bar happens at frequency/4. Then, you can find the frequency for the beat by multiplying it by 3 (since the meter is 3/4 - aka, 3 beats per bar), and ...


2

The top and bottom notes are in a speed ratio of 4:3. This means that if the upper pitch is F4, the lower pitch will be C4. Since BPM = quarter-notes per minute, and one quarter-note = one frequency cycle, then to convert beats to Hertz, we divide BPM by 60. (That is, convert quarter-notes per minute to quarter-notes per second.) C4 is approximately 261.63 ...


Top 50 recent answers are included