New answers tagged beats
2
Some way to get this automatically:
#(define (Beat_counter_engraver context)
(let ((measpos #f) (grouping #f) (basemom #f) (beatmom #f))
(define (mom->dur mom)
(let ((pair (moment->fraction mom)))
(/ (car pair) (cdr pair))))
(define (is-beat-moment? count gping beatcount)
(if (= (* count (mom->dur basemom)) (mom->dur ...
4
The target frequency (F4) is approximately 349.23Hz.
You have to find a common divisor between those two frequencies, which coincidentally is the bar.
So, assuming the frequency above, you can find that each bar happens at frequency/4. Then, you can find the frequency for the beat by multiplying it by 3 (since the meter is 3/4 - aka, 3 beats per bar), and ...
2
The top and bottom notes are in a speed ratio of 4:3. This means that if the upper pitch is F4, the lower pitch will be C4.
Since BPM = quarter-notes per minute, and one quarter-note = one frequency cycle, then to convert beats to Hertz, we divide BPM by 60. (That is, convert quarter-notes per minute to quarter-notes per second.)
C4 is approximately 261.63 ...
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