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The first mordent in this measure will be played as D , C# , D. The second mordent in the same measure doesn't have a sharp like the first mordent. Will the sharp accidental of the first mordent affect the second mordent since they are both in the same measure? I don't believe that it will but I just wanted to hear your opinion. I believe that the second mordent will be played as D , C , D. But I will like to hear your opinion. Will the accidental of the first mordent turn the C in the second mordent to C#?

The first mordent in this measure will be played as D , C# , D. The second mordent in the same measure doesn't have a sharp like the first mordent. 

Will the sharp accidental of the first mordent affect the second mordent since they are both in the same measure?

There is a very similar question (Would an accidental in a mordant still be effective for the whole measure?); however, the question itself is not specific to this situation, and although the primary answer addresses it, it's ambiguous.

I'm looking for a documented answer to this specific case.

The first mordent in this measure will be played as D , C# , D. The second mordent in the same measure doesn't have a sharp like the first mordent. Will the sharp accidental of the first mordent affect the second mordent since they are both in the same measure? I don't believe that it will but I just wanted to hear your opinion. I believe that the second mordent will be played as D , C , D. But I will like to hear your opinion.

The first mordent in this measure will be played as D , C# , D. The second mordent in the same measure doesn't have a sharp like the first mordent. Will the sharp accidental of the first mordent affect the second mordent since they are both in the same measure? I don't believe that it will but I just wanted to hear your opinion. I believe that the second mordent will be played as D , C , D. But I will like to hear your opinion. Will the accidental of the first mordent turn the C in the second mordent to C#?